Blindfold Cubing

A worked example...

The move M on this site may be the opposite to what you understand; here it corresponds to the following before and after picture:

Setup the cube

Do the moves: R2U'FD'LU2L'DB'ULB'DL2FR'L'R2 on a solved cube.

Orient the corners: step one

Starting with step 1 of the method, the twist of U is 0, so pairs to operate upon are in same layer (ie U or D).

orientate corners rotating pairs (21),(43),(56),(86)
(U')(LD2L'F'D2F)(U)-()(F'D2FLD2L')() for pair 1
(U)(LD2L'F'D2F)(U')-(U2)(F'D2FLD2L')(U2) for pair 2

Rotate cube forward 180 degrees so that U becomes D and vice versa, whilst L remains L and R remains R, plus F becomes B and vice versa.

()(LD2L'F'D2F)()-(U')(F'D2FLD2L')(U) for pair 3
(U)(LD2L'F'D2F)(U')-(U')(F'D2FLD2L')(U) for pair 4

Rotate cube forward 180 degrees so that U becomes D and vice versa, whilst L remains L and R remains R, plus F becomes B and vice versa. This undoes the cube rotation done earlier.

Orient the edges: step two

Top band to flip has: 3
Middle band to flip has: 6,8
Bottom band to flip has: 12

do pair (3,12) with
(U'R2U)
(MUMUMU2M'UM'UM'U2)
(U'R2U)
do pair (6,8) with
(LRU)
(MUMUMU2M'UM'UM'U2)
(U'R'L')

Position the corners: step three and four

Writing the corners in terms of cycles we find the parity is even, and thus we skip step 3 of the method.

(1357)(2)(48)(6) has parity=3+0+1+0=4 which is even

We can now place corners as in step 4 of the method:

getting the corners to move in the U or D layer first
(DR2DR2-U2)(LF'LB2L'FLB2L2)(U2-R2D'R2D') changes (1357)(2)(48)(6) to (17)(2)(3)(48)(5)(6)

getting the corners to move in the U or D layer first
(UR2)
()(LD2L')()(U)(LD2L')(U')()(LD2L')() and
U2-()(LD2L')()(U)(LD2L')(U')()(LD2L')()-U2
(R2U')

Position the edges: (step 3) and step 5

Writing the edges in terms of cycles we have (2,9)(3,10,12)(4,6,5,11,)(1,8,7). Since the parity of the corners was even, step 3 was not required, hence we don't need to take account of this in doing this step.

Solve (3,10,12) with (3,10)+(3,12), first putting all in the U or D layer avoiding single turns of L or R.
(L2R2)
((U2)(M'DM)(U2)) ((U')(M'D'M)(U)) ((U2)(M'DM)(U2))
((U2)(M'D'M)(U2)) ((U)(M'DM)(U')) ((U2)(M'D'M)(U2))
(R2L2)

Solve (1,8,7) with (1,8)+(1,7), first putting all in the U or D layer avoiding single turns of L or R.
(U'F'B)
((U)(M'DM)(U')) (()(M'D'M)()) ((U)(M'DM)(U'))
((U)(M'D'M)(U')) ((U2)(M'DM)(U2)) ((U)(M'D'M)(U'))
(B'FU)

Reduce (4,6,5,11) to (4,11) with (4,6)+(4,5), first putting all in the U or D layer avoiding single turns of L or R.
(FB')
((U)(M'DM)(U')) ((U2)(M'D'M)(U2)) ((U)(M'DM)(U'))
((U)(M'D'M)(U')) (()(M'DM)()) ((U)(M'D'M)(U'))
(BF')

Finally complete (4,11) and (2,9) as follows:
(F2B2)
((U)(M'DM)(U')) ((U2)(M'D'M)(U2)) ((U)(M'DM)(U'))
((U')(M'D'M)(U)) (()(M'DM)()) ((U')(M'D'M)(U))
(B2F2)

Summary

Thus to perform the entire solution for this random arrangement of the cube you needed to remember the cube was arranged as follows:

Corners -

(1357)(2)(48)(6) has parity=3+0+1+0=4 which is even
rotating pairs (21),(43),(56),(86)

Edges -

Top band to flip has: 3
Middle band to flip has: 6,8
Bottom band to flip has: 12

cycle (2,9)(3,10,12)(4,6,5,11,)(1,8,7)